1. Nilai p yang memenuhi |p|= 10 adalah..
Jawab :
(+) p = 10
(- ) -(p) = 10
- p = 10
p = 10/-1
p = -10
* Jadi yang memenuhi nilai p = 10 /
nilai p =-10
2.Jika |3k| = 6 ,nilai k yang memenuhi ...
Jawab:
(+) 3k = 6
k = 6/3
k = 2
(-) -(3k) = 6
-3k = 6
k = 6/-3
k = -2
*Jadi yang memenuhi nilai k=2 / k = -2
3.Penyelesaian persamaan |z+5|=5 ...
Jawab :
(+) z +5 = 5
z = 5 - 5
z = 0
(-) -(z +5) = 5
-z - 5 = 5
-z = 5 +5
-z = 10
z = 10/-1
z = -10
* Jadi penyelesaian persamaan |z+5|= 5 adalah 0 atau -10
4.Himpunan penyelesaian |5x-6|-4 =10 ...
Jawab :
|5x-6|- 4 =10
|5x-6| = 10+4
|5x-6| = 14
(+) 5x-6 = 14
5x = 14+6
5x = 20
x = 20/5
x = 4
Tes x= 4
|5x -6| = 14
|5.4-6|=14
|20-6| = 14
|14| = 14
14 = 14 (x=4 memenuhi)
(-) -(5x-6) = 14
-5x+6 = 14
- 5x = 14 -6
- 5x = 8
x = 8/-5
Tes x= 8/-5
|5x -6| = 14
|5.(8/-5)-6|= 14
| -8 -6| = 14
|-14| = 14
14 = 14 (x= 8/-5 memenuhi)
* Jadi Hp {4 , 8/-5 }
5.Penyelesaian persamaan |2x-3|=|-x|...
Jawab :
|2x-3|=|-x|
(+) 2x - 3 = -x
2x +x = 3
3x= 3
x = 3/3
x = 1
(-) -(2x-3)= -x
-2x +3= -x
-2x + x = -3
- x = -3
x = -3/-1
x = 3
* Jadi x= 3 atau x =1
6. Nilai q yang memenuhi |-6q -200|=160
Jawab :
(+) -6q - 200 = 160
- 6q = 160 +200
- 6q = 360
q = 360/-6
q = -60
tes q = -60
|-6q -200| = 160
|-6.-60-200| = 160
|360 - 200| = 160
|160| = 160
160 = 160
(-) -(-6q -200) = 160
6q+ 200 = 160
6q = 160 - 200
6q = -40
q = -40/6
tes q = -40/6
|-6q -200| = 160
|-6.(-40/6)-200 = 160
| 40 - 200| = 160
|-160| = 160
160 = 160
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